Question

How do you find the vertex of `f(x) = x^2 + 6x - 2`?

Answer 1

The vertex is `V=(-3;-11)`

Explanation:

The coordinates of a vertex of a parabola `f(x)=ax^2+bx+c` are given by:

`V=(-b/(2a);(-Delta)/(4a))`

But instead of calculating `Delta` you can also calculate `q` as `f(p)` i.e. substitute `p` for `x` in `f(x)`.