Question

How do you find the vertex of `y=2x^2 +11x-6`?

Answer 1

So, the solution set - or vertex set - is `(-11/4,-169/8)`

Explanation:

The x of the vertex(`x-vertex`) is found using the formula:
`"x-vertex" = -b /(2a)`, in this case: `"x-vertex" = -11/4`.
The y of the vertex(`y-vertex`) is found using the formula:
`"y-vertex" = - triangle/(4a) = - (b^2 -4ac) / (4a)`, in this case: `"y-vertex" = - [121 - (4 " x " 2" x"-6)] / (4 " x "2) =- 169/8`.
So, the solution set - or vertex set - is `(-11/4,-169/8)`