How do you find the vertex of y=2x^2-4x-2y=2x2−4x−2?

1 Answer
Binayaka C.
Jan 2, 2016

Co-Ordinate of Vertex is (1,-4)

Explanation:

This is equation of a Parabola , the general form of which is ax^2+bx+cax2+bx+c . So here a=2 ; b=-4 ; c=-2a=2;b=−4;c=−2 Let the Co-ordinate of Vertex be x_1,y_1x1,y1 . Now we know x_1 = -b/(2*a)x1=−b2⋅a
:. x_1 = 4/4 =1 Now plugging in x_1 in the equation we get y_1=2*1-4*1-2 or y_1 = -4 So The Co-Ordinate of Vertex
is (1,-4) [Answer]

Related questions
See all questions in Vertex Form of a Quadratic Equation
Impact of this question
7340 views around the world
You can reuse this answer
Creative Commons License