How do you find the vertex of $y= -x^2+18x-75$ ?

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Answer 1 · 2015-11-25T23:17:57

Find vertex of y = -x^2 + 18x - 75

Ans: Vertex (9, 6)

x-coordinate of vertex:
$x = (-b/(2a)) = (-18/-2) = 9$
y-coordinate of vertex:
y = y(9) = - 81 + 162 - 75 = 6.

How do you find the vertex of y= -x^2+18x-75y= -x^2+18x-75?