Question

How do you find the vertex of `y=x^2 -2x-15`?

Answer 1

Vertex (1, -16)

Explanation:

`y(x) = x^2 - 2x - 15`
x-coordinate of vertex:
`x = -b/(2a) = 2/2 = 1`
y-coordinate of vertex --> when x = 1 -->
y(1) = 1 - 2 - 15 = - 16
Vertex (1, -16)