How do you find the vertex of y = x^2 + 2x - 3?

1 Answer
Jan 23, 2017

When given an equation of a parabola, y(x) = ax^2 + bx + c, the x coordinate of the vertex, h = -b/(2a), and the y coordinate, k = y(h)

Explanation:

For the given equation, a = 1, b = 2, and c = -3

The x coordinate is:

h = -b/(2a)

h = -2/(2(1))

h = -1

The y coordinate is:

k = y(-1)

k = (-1)^2 + 2(-1) - 3

k = -4

The vertex is the point (-1,-4)