How do you find the vertex of $y = x^2 - 6x + 7$ ?

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Answer 1 · 2018-04-14T22:08:15

$(3, -2)$

The equation is in standard form: $y=ax^2+bx+c$

Finding the vertex of an equation in standard form: $((-b)/(2a), f((-b)/(2a)))$

Here, $a$ is $1$ and $b$ is $-6$

$(-(-6))/(2*1)$

$6/2$

$3 rarr$ The x-coordinate of the vertex is $3$ .

$f(3)=3^2-6*3+7$

$f(3)=9-6*3+7$

$f(3)=9-18+7$

$f(3)=-9+7$

$f(3)=-2$

How do you find the vertex of y = x^2 - 6x + 7y = x^2 - 6x + 7?