Question

How do you find the vertex of `y = x^2 - x + 2`?

Answer 1

Complete the square to establish vertex form

Explanation:

Using completing the squares with `-1/2` (half of `b` from `y = ax^2 + bx + c`) gives
`y = (x - 1/2)^2 -1/4 +2`
So `y = (x-1/2)^2 +7/4`
Hence the vertex is `(1/2,7/4)`