How do you find the vertex of $y= (x-3)(x+3)$ ?

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Answer 1 · 2015-11-26T20:09:09

Find vertex of y = (x - 3)(x + 3)

Ans: Vertex (0 -9).

$y = (x - 3)(x + 3) = x^2 - 9.$
x-coordinate of vertex: $x = (-b)/(2a) = 0$
y-coordinate of vertex: $y = y(0) = - 9$
Vertex (0, -9)

How do you find the vertex of y= (x-3)(x+3)y= (x-3)(x+3)?