Question

How do you find the zeros of `y=x(x-1)(x+2)^2`?

Answer 1

0,1,`-2 and -2`

Explanation:

Equate each factor of yr to 0.
`-2` is a double root.
The points at which this curve meets the x-axis are `( 0, 0 , ( 1, 0 ) and ( -2, 0 )`
At the double point (`-2`, 0 ), `dy/dx` = 0.