Question

How do you find three consecutive integers whose sum is 171?

Answer 1

Let the integers be `n-1`, `n` and `n+1`.

Then

`171 = (n-1)+n+(n+1) = n-1+n+n+1 = 3n`

Divide both ends by `3` to get

`n=57`

So the three consecutive integers are `56`, `57`, `58`.