Question

How do you find three consecutive integers whose sum is 42?

Answer 1

If we represent the smallest of the three consecutive integers as `x` then the other two integers are `(x+1)` and `(x+2)`

We are told
`(x) + (x+1) + (x+2) = 42`

`rarr 3x+3 = 42`

`rarr 3x = 39`

`rarr x = 13`

and the three consecutive integers are 13, 14, and 15.