How do you find two consecutive odd integers whose sum is 36?

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Answer 1 · 2018-04-06T19:09:49

$17$ $17$ and $19$ $19$ .

Let $n$ $n$ denote the first odd integer.
If the two integers are consecutive and odd, then the second number is $n + 2$ $n+2$ .

Hence, $n + n + 2 = 36$ $n+n+2=36$

$\Rightarrow 2 n = 34$ $\implies 2n=34$

$\Rightarrow n = 17$ $\implies n=17$ .

Therefore, the numbers are $17$ $17$ and $19$ $19$ .

Answer 2 · 2018-04-06T19:29:55

$:. 17+19 = 36$

If the odd numbers are consecutive, they must be on either side of half of 36.

$18+18 = 36$

$:. 17+19 = 36$