How do you graph and label the vertex and axis of symmetry of $y = - (x - 3) (x + 1)$ $y=-(x-3)(x+1)$ ?

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How do you graph and label the vertex and axis of symmetry of $y = - (x - 3) (x + 1)$ $y=-(x-3)(x+1)$ ?

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Answer 1 · 2017-09-30T03:23:42

Vertex $(1, 4)$ $(1,4)$
Axis of symmetry $x = 1$ $x=1$

Explanation:

Given -

$y = - (x - 3) (x + 1)$ $y=-(x-3)(x+1)$

$y = (- x + 3) (x + 1)$ $y=(-x+3)(x+1)$
$y = - x^{2} + 3 x - x + 3$ $y=-x^2+3x-x+3$
$y = - x^{2} + 2 x + 3$ $y=-x^2+2x+3$

Vertex

$x = \frac{- b}{2 a} = \frac{- 2}{- 2} = 1$ $x=(-b)/(2a)=(-2)/(-2)=1$

At $x = 1$ $x=1$

$y = - (1^{2}) + 2 (1) + 3 = - 1 + 2 + 3 = 4$ $y=-(1^2)+2(1)+3=-1+2+3=4$

Vertex $(1, 4)$ $(1,4)$
Axis of symmetry $x = 1$ $x=1$

Take a few values above and below $x = 1$ $x=1$
Form a table, after finding the $y$ $y$ values.
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Graph it.
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How do you graph and label the vertex and axis of symmetry of $y = - (x - 3) (x + 1)$ $y=-(x-3)(x+1)$ ?

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Explanation:

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How do you graph and label the vertex and axis of symmetry of y=-(x-3)(x+1)y=−(x−3)(x+1)y=-(x-3)(x+1)?

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How do you graph and label the vertex and axis of symmetry of $y = - (x - 3) (x + 1)$ $y=-(x-3)(x+1)$ ?