Question

How do you graph `f(x)=2+ln x`?

Answer 1

`f(x) = 2+lnx` is shifted up 2 units from `f(x)=lnx`

Explanation:

The parent function is `lnx` which has a vertical asymptote at `x = 0` and passes through the point `(1, 0)`

`f(x) = 2+lnx` is shifted up 2 units from `f(x)=lnx`

`y = lnx`:
graph{lnx [-10, 10, -5, 5]}

`y = lnx+2`:
graph{ln(x) +2 [-10, 10, -5, 5]}