How do you graph $f(x)=2+ln x$ ?

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Answer 1 · 2017-02-22T07:56:57

$f(x) = 2+lnx$ is shifted up 2 units from $f(x)=lnx$

The parent function is $lnx$ which has a vertical asymptote at $x = 0$ and passes through the point $(1, 0)$

$f(x) = 2+lnx$ is shifted up 2 units from $f(x)=lnx$

$y = lnx$ :
graph{lnx [-10, 10, -5, 5]}

$y = lnx+2$ :
graph{ln(x) +2 [-10, 10, -5, 5]}

How do you graph f(x)=2+ln xf(x)=2+ln x?