How do you graph $f(x)=4(2^x)+1$ and state the domain and range?

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Answer 1 · 2018-06-17T04:05:05

Dom(f)= R
Range(f)={y|1<y}

$4(2^x)+1$
$=(2^2)(2^x)+1$
$=2^(x+2)+1$

graph of $f(x)=4(2^x)+1$ is
vertical shift=-2
horizontal shift=1

shift graph of $f(x)=2^x$ to left 2 units and upward 1 unit.

How do you graph f(x)=4(2^x)+1f(x)=4(2^x)+1 and state the domain and range?