How do you graph $f (x) = log (0.2) (x + 6)$ $f(x) = log(0.2) (x + 6)$ ?

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Answer 1 · 2016-05-29T16:11:03

This is a straight line through $(- 6, 0) and (0, - 4.2)$ $(-6, 0) and (0, -4.2)$ .

$log .2 = - 0.7$ $log .2 =-0.7$ , nearly..

So, the equation becomes $f (x) = y = - 0.7 x - 4.2$ $f(x)=y=-0.7x-4.2$ .

The slope of this line is $- 0.7$ $-0.7$ , nearly, and the y-intercept is #-4.2, nearly.

The x-intercept = -6.

How do you graph f(x)=log(0.2)(x+6)f(x) = log(0.2) (x + 6)?