How do you graph F(x)=log13(x+5)?

1 Answer
Nov 22, 2016

This is a decreasing log with a VA at x=5.

Explanation:

f(x)=log13(x+5)

The vertical asymptote is found by setting x+5 equal to zero.

x+5=0x=5

The base of the log is 13. A base that is less than one indicates that the graph is a decreasing log.

To find the x intercept, set f(x)=0

0=log13(x+5)

Rewrite as an exponential and solve.

(13)0=x+5

1=x+5

x=4 when f(x)=0 the x intercept is (4,0)

The y intercept is found by setting x=0

y=log13(0+5)

y=log135

Use the change of base formula logab=logbloga

y=log5log(13)=1.46the y intercept is (0,1.46)

See the graph below.

![desmos.com](useruploads.socratic.orguseruploads.socratic.org)

Alternatively, the function can be rewritten as an exponential and an xy table can be constructed by choosing values of y and finding corresponding x values.

y=log13(x+5)

x+5=(13)y

x=(13)y5

Then choose values of y such as 2,1,0,1,2 and find the corresponding values of x. Plot the resulting xy coordinates.