How do you graph $F (x) = {log}_{2} (x - 3)$ $F(x)= log_2(x-3)$ ?

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How do you graph $F (x) = {log}_{2} (x - 3)$ $F(x)= log_2(x-3)$ ?

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Answer 1 · 2016-05-24T16:51:07

By inversion, $x - 3 = 2^{y}$ $x-3=2^y$ , and so, $x = 3 + 2^{y}$ $x=3+2^y$ .
The graph rises from $(3, - \infty)$ $(3, -oo)$ to (4, 0) anr rises to $y = \infty$ $y=oo$ through (7, 2), (11, 3), (19, 4),..(

Explanation:

x = 3 is the vertical asymptote and the graph is on the right side of the asymptote, with x > 3.

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How do you graph $F (x) = {log}_{2} (x - 3)$ $F(x)= log_2(x-3)$ ?

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How do you graph $F (x) = {log}_{2} (x - 3)$ $F(x)= log_2(x-3)$ ?