How do you graph $f (x) = {log}_{3} (1 - x)$ $f(x)=log_3(1-x)$ ?

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Answer 1 · 2017-10-21T21:11:50

See explanation

As a general case: ${log}_{a} (x) = \frac{{log}_{b} (x)}{{log}_{b} (a)}$ $log_a(x)=log_b(x)/(log_b(a))$

So lets apply this approach

We can easily use ${log}_{10}$ $log_10$ so this is the one I chose.

Set $d y = \frac{{log}_{10} (1 - x)}{{log}_{10} (3)}$ $color(white)("d") y = log_10(1-x)/log_10(3)$

Note that this becomes undefined at $x = 1$ $x=1$

${log}_{10} (1) = 0 d \to d 10^{0} = 1$ $log_10(1) = 0color(white)("d") -> color(white)("d")10^0=1$

Tony B Tony B

How do you graph f(x)=log_3(1-x)f(x)=log3(1−x)f(x)=log_3(1-x)?