How do you graph $g (x) = \frac{1}{4} {log}_{2} (x - 4) - 3$ $g(x) = 1/4log_2 (x - 4) - 3$ ?

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Answer 1 · 2017-02-11T14:44:31

See graph and explanation.

To make g real, $x > 4$ $x > 4$ .

x-intercept ( y = 0 ) :4100, from, ${log}_{2} (x - 4) = 12$ $log_2(x-4)=12$ , giving x=4+2^12

Converting to ln,

g=1/4(ln(x-4)/ln 2)-3 and the Socratic graph is created.

Ax $x \to \infty, g \to \infty$ $x to oo, g to oo$ .

Also, as $x \to 4, y \to - \infty$ $xto4, y to -oo$ , revealing the asymptote x = 4..

x-intercept ( y = 8 ) :4100, from, ${log}_{2} (x - 4) = 12$ $log_2(x-4)=12$ , giving x=4+2^12

graph{(1/4ln(x-4)/ln2-3-y)=0 [0, 10000, -5, 5]}

The graph is no to uniform scale in both directions. Yet, it reveals features

How do you graph g(x) = 1/4log_2 (x - 4) - 3g(x)=14log2(x−4)−3g(x) = 1/4log_2 (x - 4) - 3?