How do you graph ln(x)?

1 Answer
Jun 28, 2018

Reflect the graph of e^xex in the line y=xy=x...

Explanation:

First think about how you can graph e^xex

Note that e ~~ 2.71828182844e2.71828182844, so e^xex is a smooth exponential curve passing through:

(0, 1)(0,1)

(1, e) ~~ (1, 2.718)(1,e)(1,2.718)

(2, e^2) ~~ (2, 7.389)(2,e2)(2,7.389)

(3, e^3) ~~ (3, 20.0855)(3,e3)(3,20.0855)

...

(-1, e^(-1)) ~~ (-1, 0.3679)(1,e1)(1,0.3679)

(-2, e^(-2)) ~~ (-2, 0.1353)(2,e2)(2,0.1353)

(-3, e^(-3)) ~~ (-3, 0.0498)(3,e3)(3,0.0498)

...

So it looks like this:
graph{e^x [-11.04, 8.96, -1.28, 8.72]}

To get the graph of its inverse ln(x)ln(x), we can reflect this graph in the diagonal line y=xy=x to get:
graph{ln x [-5.04, 14.96, -6.96, 3.04]}