Question

How do you graph `r = 3 sec (theta + 90°)`?

Answer 1

Draw the straight line parallel to the compounded initial line `theta= 0 and theta = pi`, at a distance 3. in the direction `theta = 3/2pi`.

Explanation:

This is the polar form for`y = -3`

Here, `r = 3sec(theta+ 90^o)=3(-csc theta)=-3/sin theta`

So, y = r sin theta = -3

Draw the straight line parallel to the compounded initial line `theta= 0 and theta = pi`, at a distance 3. in the

direction `theta = 3/2pi`.