Question

How do you graph the equation `3x+8y=32`?

Answer 1

See a solution process below:

Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For `x = 0`

`(3 * 0) + 8y = 32`

`0 + 8y = 32`

`8y = 32`

`(8y)/color(red)(8) = 32/color(red)(8)`

`y = 4` or `(0, 4)`

Second Point: For `x = 8`

`(3 * 8) + 8y = 32`

`24 + 8y = 32`

`-color(red)(24) + 24 + 8y = -color(red)(24) + 32`

`0 + 8y = 8`

`8y = 8`

`(8y)/color(red)(8) = 8/color(red)(8)`

`y = 1` or `(8, 1)`

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.1)((x-8)^2+(y-1)^2-0.1)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x+8y-32)(x^2+(y-4)^2-0.1)((x-8)^2+(y-1)^2-0.1)=0 [-20, 20, -10, 10]}