How do you graph the exponential function $f (x) = {(\frac{1}{2})}^{x} - 3$ $f(x)=(1/2)^x -3$ ?

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How do you graph the exponential function $f (x) = {(\frac{1}{2})}^{x} - 3$ $f(x)=(1/2)^x -3$ ?

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Answer 1 · 2016-10-06T02:00:12

It has a vertical shift of -3. ${(\frac{1}{2})}^{X}$ $(1/2)^X$ will decrease over time, min of -3 (asymptote), y-int = -2

Explanation:

${(\frac{1}{2})}^{x}$ $(1/2)^x$ has a minimum of zero (not including zero), as x approaches infinity, so 0-3 = -3 is a horizontal asymptote graph{(1/2)^x-3 [-10, 10, -5, 5]}

It has a y-intercept of -2 because 1-3 = -2
${(\frac{1}{2})}^{0} = 1$ $(1/2)^0=1$

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How do you graph the exponential function $f (x) = {(\frac{1}{2})}^{x} - 3$ $f(x)=(1/2)^x -3$ ?

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Explanation:

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How do you graph the exponential function $f (x) = {(\frac{1}{2})}^{x} - 3$ $f(x)=(1/2)^x -3$ ?