How do you graph the function $y=5(2)^x$ ?

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Answer 1 · 2017-09-11T15:56:33

See below.

To find significant points notice that when $x = 0$ we have $5(2)^0 => 5(1) = 5$

So y axis intercept is at $( 0 , 5 )$ :

If $x < 0$ we have $5/2^x$ , as $x -> oo$ , $5/2^x -> 0$

So the $x$ axis is a horizontal asymptote.

if $x > 0$

$5(2)^x -> oo$ , as $x -> oo$

See graph:

graph{5(2)^x [-10, 10, -5, 50]}

How do you graph the function y=5(2)^xy=5(2)^x?