How do you graph the inequality $y \geq 2 x^{2} + x - 3$ $y>=2x^2+x-3$ ?

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How do you graph the inequality $y \geq 2 x^{2} + x - 3$ $y>=2x^2+x-3$ ?

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Answer 1 · 2018-02-24T09:06:55

Just make the graph of $y = 2 x^{2} + x - 3$ $y=2x^2+x-3$ and shade the region inside that parabola, that will be the solution set (Graph) of the given inequality $y \geq 2 x^{2} + x - 3$ $y>=2x^2+x-3$ .

Explanation:

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The graph of the inequality $y \geq 2 x^{2} + x - 3$ $y>=2x^2+x-3$ .

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How do you graph the inequality $y \geq 2 x^{2} + x - 3$ $y>=2x^2+x-3$ ?

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How do you graph the inequality y≥2x2+x−3y>=2x^2+x-3?

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How do you graph the inequality $y \geq 2 x^{2} + x - 3$ $y>=2x^2+x-3$ ?