How do you graph the inequality $y<=-3abs(x-2)+4$ ?

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Answer 1 · 2016-12-02T04:21:20

Upon the collar-graph and the neck within, $y<=-3|x-2|+4$ . The vertex of the collar is (2, 4)

$y<=-3|x-2|+4$ is the combined equation for the pair

$y<=-3(x-2)+4, x>=2$ and

$y<=-3(-(x-2))+4, x<=2$

representing two straight lines meeting at ( 2, 4 ).

See the graph.

Upon the collar-graph and the neck within, $y<=-3|x-2|+4$ .

graph{y+3|x-2|-4=0 [-40, 40, -20, 20]}

How do you graph the inequality y<=-3abs(x-2)+4y<=-3abs(x-2)+4?