How do you graph the line $y = 5x - 15$ ?

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Answer 1 · 2018-05-31T12:13:23

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$

$y = (5 xx 0) - 15$

$y = 0 - 15$

$y = -15$ or $(0, -15)$

Second Point: For $x = 3$

$y = (5 xx 3) - 15$

$y = 15 - 15$

$y = 0$ or $(3, 0)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+15)^2-0.3)((x-3)^2+y^2-0.3)=0 [-40, 40, -20, 20]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-5x+15)(x^2+(y+15)^2-0.3)((x-3)^2+y^2-0.3)=0 [-40, 40, -20, 20]}

How do you graph the line y = 5x - 15 y = 5x - 15?