How do you graph the polar equation $r=3sec(theta+pi/3)$ ?

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Answer 1 · 2017-01-31T02:09:17

See graph. I have used the Cartesian form $x-sqrt3y-6=0$ , instead.

$rcos(theta+pi/3)=(rcostheta)cos(pi/3)-rsinthetasin(pi/3)$

$=1/2(x-sqrt3y)=3$

graph{x-sqrt3y-6=0 [-10, 10, -5, 5]}

How do you graph the polar equation r=3sec(theta+pi/3)r=3sec(theta+pi/3)?