Question

How do you graph using slope and intercept of `2x - 3y = -11`?

Answer 1

Please see below.

Explanation:

To graph `2x-3y=-11`, we have to convert this into slope intercept form.

Slope intercept form of the equation is `y=mx+c`, where `m` is slope and `c` is the intercept made by line on `y` axis.

As `2x-3y=-11`, we have `3y=2x+11` or `y=2/3x+11/3`

Hence slope of `2x-3y=-11` is `2/3` and intercept made by line on `y` axis is `11/3`.

So first mark the point `(0,11/3)` and then one needs to draw a line with slope `2/3` from this point. As it is upward sloping, one needs to add `2` units on ordinate and `3` units on abscissa.

So other point could be `(3,2+11/3)` or `(3,5 2/3)` and the line should look like

graph{2x-3y=-11 [-20, 20, -10, 10]}