Question

How do you graph using slope and intercept of `2x+y=8`?

Answer 1

(see below for method used in generating this graph)

Explanation:

The slope of a line in the form `Ax+By=C` is `(-A/B)`

The y-intercept is the value of `y` when `x=0`

In this case `2x+y=8`
`color(white)("XXX")` slope `= -2/1=-2`
and
`color(white)("XXX")` the `y` intercept is `8` (since `2xx0+y=8 rarr y=8`)

Based on the `y`-intercept we know that one point on the line is at `(x,y)=(0,8)`

The slope of `(-2)` tells us that for every unit increment (i.e. `+1`) of the `x` value, the `y` value changes by `(-2)`

So we can build a table of a few Sample points:
`color(white)("XXX"){:(ul(x),color(white)("xxx"),ul(y)),(0,,8),(1,,6),(2,,4),(3,,2) :}`

Plotting these coordinates on the Cartesian plane and drawing a straight line through them should give a graph that looks like the Answer above.