How do you graph using slope and intercept of 3/2x - 1/3y = 7/3?

1 Answer
Dec 31, 2015

Manipulate so that the equation is in the form y=mx+b, where m is the slope and b is the y-intercept.

First, to isolate the y-term, subtract 3/2x from both sides.

-1/3y=-3/2x+7/3

To isolate just y, multiply both sides by -3.

y=9/2x-7

This means that the function has an intercept at (0,-7).

The slope is 9/2. Slope is also known as "rise over run", since it represents the change in y-values over the change in x-values.

Thus, the "rise" is 9 for every "run" of 2. This means that if you have the point (0,-7), you know that the point (0+2,-7+9)=>(2,2) is also on the line.

Graph (2,2) and draw the line. If you wish, you can continue going up 9 units and right 2 units to draw in more points. You can also go down 9 units and left 2 units.

graph{3/2x-1/3y=7/3 [-28.47, 44.6, -15.8, 20.72]}