How do you graph using slope and intercept of $-3x+7y=-1$ ?

Question

2736 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-13T13:26:15

As below.

Standard form of equation for slope-intercept is $y = mx + c$

Slope = m, y-intercept = c.

$-3x + 7y = -1$

$7y = 3x - 1$

$y = (3/7)x - (1/7)$

graph{(3/7)x - 1/7 [-10, 10, -5, 5]}

How do you graph using slope and intercept of -3x+7y=-1-3x+7y=-1?