Question

How do you graph using slope and intercept of `4x-2y=48`?

Answer 1

Put it into the form `y=mx+c`

`4x=2y+48`

`4x-48=2y`

`2x-24=y`

`y=2x-24`

slope is 2 and the intercept is (0,-24)

Answer 2

See below for graph and method

Explanation:

Re-arranging the given equation: `4x-2y=48` into slope-intercept form:
`color(white)("XXX")4x-48=2y`

`color(white)("XXX")y=2x-24`
`color(white)("XXX")` which is the slope intercept form
`color(white)("XXX")` with slope `2`, and
`color(white)("XXX ")y`-intercept `(-24)`

The `y` intercept of `(-24)` tells us that one of the points on our line is at `(x_0,y_0)=(0,-24)`

The slope of `2` tells us that for every increase of `1` in the value of `x`, the value of `y` will increase by `2`.
So some other points that we could use to plot out line are:
`color(white)("XXX")(x_1,y_1)=(0+1,-24+2)=(1,-22)`
or
`color(white)("XXX")(x_24,y_24)=(0+24,-24+(2 * 24))=(24,24)`

graph{(x^2+(y+24)^2-0.3)((x-1)^2+(y+22)^2-0.3)((x-24)^2+(y-24)^2-0.3)(4x-2y-48)=0 [-50.63, 81, -40.23, 25.64]}