Question

How do you graph using slope and intercept of `8x + 7y = -16`?

Answer 1

Slope `m=-8/7` and y-intercept `b=-16/7~=-2.285`

Explanation:

Once the slope and the y-intercept has been computed, use a graphing paper. Then, you can now locate the intercept
at `(0, b)=(0, -16/7)=(0, -2.285)`

when you already located this point, count 7 units to the left then count 8 units up. This means, when you count 7 units to the left, you temporarily stop at (-7, -2.285). Afterwards, you will count 8 units upward to find (-7, 5.715).

At this point, you now have two points `(0, -2.285)` and
`(-7, 5.715)`.

Connecting these two points will be the graph of the line `8x+7y=-16`

graph{8x+7y=-16[-30,30,-15,15]}

God bless... I hope my explanation is useful...