How do you graph using slope and intercept of $x-3y= -13$ ?

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Answer 1 · 2018-05-15T17:37:34

$y=1/3x+13/3$ graph{1/3x+13/3 [-20, 20, -10, 10]}

The slope-intercept form is $y=mx+b$ therefore we have to isolate the $y$ .

Begin by subtracting $x$ from both sides to get $-3y=-x-13$ (since $x$ is positive on the left.)

Next, divide both sides by $-3$ to get $y=1/3x+13/3.$

Graph by using $13/3$ on the $y$ - intercept and the using a rise of $1$ and a run of $3$ to find the next point.

How do you graph using slope and intercept of x-3y= -13 x-3y= -13?