How do you graph using slope and intercept of $-x+5y=-5$ ?

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Answer 1 · 2015-11-10T23:01:05

The slope is $1/5$ .
The y-intercept is $-1$ .
The x-intercept is $5$ .

$-x+5y=-5$ is a linear equation in standard form. Convert it to the slope intercept form by solving for $y$ .

$-x+5y=-5$

Add $x$ to both sides.

$5y=x-5$

Divide both sides by $5$ .

$y=x/5-5/5=$

$y=1/5x-1$

$y=1/5x-1$ is the slope intercept form of a linear equation, $y=mx+b$ , where $m$ is the slope, $1/5$ and $b$ is the y-intercept, $-1$ .

The y-intercept is the value of $y$ when $x=0$ . The point of the y-intercept is $(0,-1)$ .

The x-intercept is the value of $x$ when $y=0$ .

$0=1/5x-1$

Add $1$ to both sides.

$1=1/5x$

Multiply both sides times $5$ .

$1*5=1/cancel5x*cancel5=$

$5=x$

Switch sides.

$x=5$

The x-intercept is $5$ . The point of the x-intercept is $(5,0)$ .

Plot the two points and draw a straight line through the points.

graph{y=1/5x-1 [-16.02, 16, -8.01, 8.01]}

How do you graph using slope and intercept of -x+5y=-5-x+5y=-5?