How do you graph $x^2 + y^2 = 16$ and $r = 4$ ?

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Answer 1 · 2018-04-11T20:33:19

They're the same curve. Recall that $r =sqrt(x^2 + y^2)$ .

$sqrt(x^2 + y^2) = 4$

$x^2 +y^2 =4$

Which is same as the other equation. This makes a circle with radius $2$ and centre $(0, 0)$ . Here is its graph:

graph{x^2 + y^2 = 4 [-10, 10, -5, 5]}

Hopefully this helps!

How do you graph x^2 + y^2 = 16x^2 + y^2 = 16 and r = 4r = 4?