How do you graph $x^{2} + y^{2} = 16$ $x^2 + y^2 = 16$ and $r = 4$ $r = 4$ ?

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Answer 1 · 2018-04-11T20:33:19

They're the same curve. Recall that $r = \sqrt{x^{2} + y^{2}}$ $r =sqrt(x^2 + y^2)$ .

$\sqrt{x^{2} + y^{2}} = 4$ $sqrt(x^2 + y^2) = 4$

$x^{2} + y^{2} = 4$ $x^2 +y^2 =4$

Which is same as the other equation. This makes a circle with radius $2$ $2$ and centre $(0, 0)$ $(0, 0)$ . Here is its graph:

graph{x^2 + y^2 = 4 [-10, 10, -5, 5]}

Hopefully this helps!

How do you graph x2+y2=16x^2 + y^2 = 16 and r=4r = 4?