How do you graph $y + \frac{1}{2} = - \frac{1}{3} (x + \frac{1}{2})$ $y + 1/2 = -1/3(x+1/2)$ ?

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Answer 1 · 2016-02-16T16:28:59

$y = \frac{x^{2}}{3} + \frac{x}{3} - \frac{5}{12}$ $y=x^2/3+x/3-5/12$

You need to transform the given equation into a more workable format.

Subtract $\frac{1}{2}$ $color(blue)(1/2)$ from both sides.

$y + \frac{1}{2} - \frac{1}{2} = - \frac{1}{3} {(x + \frac{1}{2})}^{2} - \frac{1}{2}$ $y+1/2color(blue)(-1/2)=-1/3(x+1/2)^2color(blue)(-1/2)$

$y + 0 = \frac{1}{3} {(x + \frac{1}{2})}^{2} - \frac{1}{2}$ $y+0=1/3(x+1/2)^2-1/2$
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Square the brackets

$y = \frac{1}{3} (x^{2} + x + \frac{1}{4}) - \frac{1}{2}$ $y=1/3(x^2+x+1/4)-1/2$

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Multiply the contents of the brackets by $\frac{1}{3}$ $1/3$

$y = \frac{x^{2}}{3} + \frac{x}{3} + \frac{1}{12} - \frac{1}{2}$ $y=(x^2)/3+x/3+1/12 -1/2$

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Simplify the constant

$y = \frac{x^{2}}{3} + \frac{x}{3} - \frac{5}{12}$ $y=x^2/3+x/3-5/12$
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Produce a table of values and plot your graph

Tony B

How do you graph y+12=−13(x+12)y + 1/2 = -1/3(x+1/2)?