How do you graph $y=(1/2)*3^x$ ?

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Answer 1 · 2017-10-08T18:42:21

See below.

First you need to find critical points:

For: $y=(1/2)*3^x$

$y$ axis intercept occurs when $x=0$ . So:

$y= (1/2)*3^0=> y=(1/2)*1=> color(red)(y=1/2)$

As:

$lim_(x->oo^+)(1/2)*3^x= oo$

For $x<0$

$3^x->1/(3^x)$

So:

$lim_(x->oo^-)(1/2)*3^x=0$

The $color(red)(x)$ axis is a horizontal asymptote:

Hope this helps.

Graph of $y=(1/2)*3^x$

graph{y=(1/2)*3^x [-16.02, 16.02, -8.01, 8.01]}

How do you graph y=(1/2)*3^xy=(1/2)*3^x?