How do you graph $y=(1/3)^x+1$ ?

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Answer 1 · 2017-12-29T21:41:24

See below.

First find common coordinates:

y axis intercept occurs when $x=0$ :

$y=(1/3)^(0)+1=2color(white)(88)$ coordinate $( 0 , 2 )$

x axis intercepts occur when $y=0$ :

$(1/3)^x+1=0$ ( no real number solutions to this )

No x axis intercepts.

as $x->oo$ , $color(white)(88)(1/3)^x+1->1$

as $x->-oo$ , $color(white)(88)(1/3)^x+1->oo$

The line $y=1$ is a horizontal asymptote.

GRAPH:

enter image source here

How do you graph y=(1/3)^x+1y=(1/3)^x+1?