How do you graph $y=2^(x+1)+3$ ?

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Answer 1 · 2018-08-05T23:41:10

The new coordinates would be

$(-2,3.5)$ , $(-1,4)$ , $(0,5)$ , $(1,7)$ , $(2,11)$

First, you want to know some points for the parent function, $y=2^x$

$(-1,.5)$
$(0,1)$
$(1,2)$
$(2,4)$
$(3,8)$

graph{2^x [-10, 10, -5, 5]}

Then we can look at this new equation and see that the y-intercept shifts up 3 from the $+3$ , so all the y coordinates shift up $3$ as well.

We also can see that the x coordinates all shift left 1 from the $x+1$ . The new coordinates would be

$(-2,3.5)$
$(-1,4)$
$(0,5)$
$(1,7)$
$(2,11)$

graph{2^(x+1) + 3 [-9.92, 10.08, -0.8, 9.2]}

How do you graph y=2^(x+1)+3y=2^(x+1)+3?