How do you graph $y=3$ using slope intercept form?

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Answer 1 · 2017-06-12T02:53:00

A horizontal straight line through $(0,3)$ or any other value of $x$ .
$y=0x+3$

The equation of a straight line in line $(m)$ and intercept $(c)$ form is: $y=mx+c$

However, in this example $y$ is independent of $x$ so the slope is $0$ . This equivalent to: $y=3 forall x in RR$

Or: $y=0x+3$

Hence, our graph is a horizontal straight line through $(0,3)$ or any other value of $x$ .
graph{0x+3 [-6.086, 6.4, -0.7, 5.545]}

How do you graph y=3y=3 using slope intercept form?