How do you graph $y=3log_2x$ ?

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Answer 1 · 2016-12-22T12:21:27

Socratic graph is inserted.

$y=3(log x/log 2),$ using $log_b a=log a/log b$

$x>0$ , to make the logarithm real.

The graph is inserted.

x-intercept ( y = 0 ): 1

As $x to oo, y to oo$ and as $x to 0, y to -oo$ .

See this logarithmic rise in the graph

graph{1/3y log 2- log x = 0 [-5, 5, -2.5, 2.5]}

How do you graph y=3log_2xy=3log_2x?