Question

How do you graph `y=-3x-3` using rise over run?

Answer 1

`:.color(green)(" Slope " = m = "(rise) / (run)" = - 3`

Explanation:

`y = -3x - 3`

`y = mx + c " is the slope-intercept form"`

`color(crimson)("Slope " = m = tan theta = " (rise) / (run) = (y-intercept) / (x-intercept)"`

`"rise " = y " when " x = 0, run = x " when " y = 0`

`:. "when " x = 0, y = -3 * 0 - 3 = -3, "y-intercept " = -3`

`"Likewise, when " y = 0, 0 = -3x -3 " or x-intercept " = -1`

`:.color(green)(m= "(rise) / (run)" = (-3)/-1 = - 3 " as " theta " in II Quadrant"`

graph{- 3x - 3 [-10, 10, -5, 5]}