The line is given in slope-intercept form, y=mx+by=mx+b, where mm is the slope and bb is the yy-coordinate of the yy-intercept, (0,b)(0,b).
By inspection, we can see that the yy-intercept is (0,1)(0,1).
The slope is -4/3−43, which we can think of as (Deltay)/(Deltax) or change in y over change in x. I think of it, in this case, as every move of 3 units to the right requires a move of 4 units down to stay on the line. So with that idea in mind, 3 units to the right from the y-intercept takes us to x=3. The corresponding 4 units down takes us to y=1-4=-3. So a second point on the line is (3,-3).
Plot the points (0,1) and (3,-3) and connect them with a straight line.
