How do you graph $y > \frac{4}{3} x^{2} - 12 x + 29$ $y>4/3x^2-12x+29$ ?

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How do you graph $y > \frac{4}{3} x^{2} - 12 x + 29$ $y>4/3x^2-12x+29$ ?

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Answer 1 · 2018-04-11T23:51:34

First, graph the function
$y = \frac{4 x^{2}}{3} - 12 x + 29 .$ $y = (4x^2)/3 - 12x + 29.$
The area that is above the parabola graph is the solution set.
graph{(4x^2)/3 - 12x + 29 [-20, 20, -10, 10]}

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How do you graph $y > \frac{4}{3} x^{2} - 12 x + 29$ $y>4/3x^2-12x+29$ ?

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