How do you graph $y=ln(x+1)$ ?

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Answer 1 · 2017-11-13T12:56:24

Assigning different values for x and getting y.

If your x is zero, your function will be $y=ln1 = 0$

If your x is 1, your function will be $y=ln2 = 0.693$

If your x is 2, your function will be $y=ln3 = 1.099$

etc. You can graph now. Note that x cannot be less than -1.

graph{ln(x+1) [-5.205, 14.795, -7.04, 2.96]}

How do you graph y=ln(x+1)y=ln(x+1)?