Question

How do you graph `y=log_4(3x+11)-5`?

Answer 1

`x > -11/3`. x-intercept ( y = 0 ) = 337.7, nearly. y-intercept ( x = 0 )= `-3.27`, nearly. Vertical (`darr` ) asymptote is `x = -11/3`. See illustrative graph

Explanation:

#x > -11/3, to make y real.

As `x to (-11/3)_+, y to -oo`.

As `x to oo, y to oo`

graph{1024(4^y)-3x-11=0 [-40, 40, -20, 20]}